# How to design a heat exchanger?

Custom-made by our thermal engineers, **heat exchanger calculation** is a complex process that requires a lot of data and many equations. Are you ready for a crash course in thermodynamics?

## How to design a heat exchanger?

For **sizing a heat exchanger**, several thermal phenomena should be considered first:

- Forced convection of both fluids: Convection is the transfer of heat between a wall and a flowing fluid, both having different temperatures. In the case of heat exchangers, it is called forced convection as it is caused by artificial circulation (pumps, turbines, fans...)
- Conduction: This is the transfer of heat which occurs naturally through the walls, plates and tubes. This phenomenon is based on the principle of thermal agitation without movement of material.
- Thermal radiation which could be considered as negligible

**WARNING**

*For clarity and brevity, we chose to simplify information and calculation methods that are exposed only partially and which refer to the simplest cases. In our daily activity, sizing request the inclusion of many other parameters and heat exchanger equation.*

**The design of a heat exchanger**addresses mainly three phases:

## 1.The choice of technology

Selection of the optimum technology is linked to:

- The thermal program (Required temperatures, efficiency…)
- The nature of the fluids
- The application
- The constraints of installation and maintenance

## 2.Thermal design

** 2.a. Validation of the thermal program**

Once the technological choices made, we will proceed to the

**design of the heat exchanger**, i.e. determining its power, size and geometry. It is first necessary to validate the data of the thermal program, with the following 3 formulas:

*P: Power (in KW or KCal/h)*

*T: temperature (in °C)*

*Q: Flowrate (in Kg/h)*

*△t: (T*

_{in}–T_{out})in °C*Cp: Specific heat (in KWh/Kg/°C)*

Example: application for cooling water at a flowrate of 10 m

^{3}/h

Thanks to those formulas, the other data can be calculated. Here we have:

i.e.

T

_{out}= 73°C

Total power: 65,000 KCal/h or 756 KW

**2.b. Calculation of the heating surface**

First, LMDT (Logarithmic mean temperature difference) shall be calculated. The LMDT is the logarithmic average of the temperature differences at each end of the heat exchanger:

*T*

_{in}1 : T_{in}cold*T*

_{in}2 : T_{in}hot*T*

_{out}1 : T_{out}cold*T*

_{out}2 : T_{out}coldOnce LMDT and Power have been calculated, the

**heat exchanger calculation**can be done as per the following formula:

*K: Heat Transfer Coefficient in KW/°C/m*

^{2}that is specific to each type of equipment and given by the manufacturer.*S : Heating area in square meters.*

**2.c. Calculation of K and incrustation**

The Heat Transfer Coefficient of an heat exchanger is given by :

*h1 and h2: Local Heat exchange Coefficients calculated as per the local geometry as well as dimensionless numbers such as Reynolds (Re), Prandlt (Pr) and Nusselt (Nu).*

*e: Wall thickness in m*

*λ: Thermal Conductivity of the wall in W/°C/m*

*R*

_{encrustation}: Resistance due to the wall foulingGetting the

**Heat Transfer Coefficient**(HTC or K) enables to find the heating area and hence sizing the heat exchanger.

## 3. Calculation of the heat exchanger pressure drop

A moving fluid undergoes energy losses due to friction on the walls (regular head loss) or mishaps (singular head losses) such as baffles, for example. This loss of energy, expressed in pressure drop (△P) must be compensated to allow the fluid to move.

When the heat exchanger is designed, the **heat exchanger pressure drop** can be calculated with different correlations determined by the characteristics of the exchange surfaces.

Steps 2 and 3 are made by interdependence and iterations, as shown in the summary diagram below:

## Heat exchanger efficiency and effectiveness

We must not confuse efficiency and effectiveness. Indeed, considering no loss by radiation, therefore the effectiveness of a heat exchanger is equal to 1.

The efficiency (yield) corresponds to the following formula:

Obtaining a yield of 100% is impossible. The yield is induced by the needs for power and temperatures of the client’s application. Hence in most cases, it is fixed upon request by the client himself.